New Assessment May Give Clinton the Popular Vote

Photo credits: AP

Get this: the Caucus (NY Times) is reporting an assessment that might give Clinton the edge in the popular vote on June 3 after all.

Here’s the deal:

“With her expected big win in Puerto Rico on June 1, a collection of votes could give her the popular vote lead without including the disputed results from Michigan and Florida. The Clinton campaign is circulating an opinion article from the Philadelphia Inquirer, which analyzes the vote possibilities. It buttresses the heart of her new argument to the superdelegates — that if she wins the popular vote across the whole country, how can they overturn the will of the people?”

The Inquirer analysis (shown in blue) as quoted by the Caucus:

Real Clear Politics keeps track of six versions of the popular-vote total. They are, in ascending order of inclusivity: (1) the popular vote of sanctioned contests; (2) the total of sanctioned contests, plus estimated votes from the Iowa, Nevada, Maine and Washington caucuses; (3) the popular vote plus Florida; (4) popular vote plus Florida and the caucuses; (5) the popular vote plus Florida and Michigan; (6) popular vote plus Florida, Michigan, and the caucus estimates. After Tuesday, Clinton now leads in two of these six counts.

If you believe that the most important precept in democratic politics is to “count every vote,” then the sixth category is the most inclusive, and here Clinton leads Obama by 71,301 votes. Of course, this includes the Michigan result, where Sen. Obama had removed his name from the ballot. So while it may be the most inclusive, it may not be the most fair.

The third and fourth counts - the ones which include Florida - seem more fair. Here, Obama is clinging to a slight lead of 146,786 votes (257,008, with the caucus estimates). However, with Puerto Rico, Montana, and South Dakota remaining, he will almost certainly finish behind her in these counts, likely by a few hundred thousand votes.

But could Clinton take over the lead in all of the popular-vote tabulations? Quite possibly. In Puerto Rico’s last major election, two million people voted. Let’s assume that turnout for this historic vote - Puerto Rico has never had a presidential primary before - will be equal to or greater than that turnout.

If Clinton were to win Puerto Rico by 20 points she would pick up at least a 400,000-vote margin. This would allow her to swamp Obama in the popular-vote counts, which include Florida, making her the leader in four of the six permutations of the popular vote. At that point, Obama would be left clinging to the least-inclusive count, which he now leads by 441,558 votes (551,780, including caucuses).

To understand how razor-thin this majority is, consider that if the Puerto Rico turnout is slightly larger than we have imagined - or Clinton’s margin is slightly greater - then Clinton would finish the primary process leading in every conceivable vote count. With two million voters, a 28 percent victory would put Clinton over the top even in the count, which excludes Florida and Michigan and includes estimates for Obama’s caucus victories.

The Caucus reports:

“Mrs. Clinton is headed to South Dakota now, where she plans to discuss the numbers at an editorial board meeting this afternoon.”